X^2-2x+0.2=0

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Solution for X^2-2x+0.2=0 equation: 



X^2-2X+0.2=0

a = 1; b = -2; c = +0.2;
Δ = b2-4ac
Δ = -22-4·1·0.2
Δ = 3.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{3.2}}{2*1}=\frac{2-\sqrt{3.2}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{3.2}}{2*1}=\frac{2+\sqrt{3.2}}{2}
$

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